f(x-1)=2x^2+2x+4

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Solution for f(x-1)=2x^2+2x+4 equation: 


Simplifying
f(x + -1) = 2x2 + 2x + 4

Reorder the terms:
f(-1 + x) = 2x2 + 2x + 4
(-1 * f + x * f) = 2x2 + 2x + 4
(-1f + fx) = 2x2 + 2x + 4

Reorder the terms:
-1f + fx = 4 + 2x + 2x2

Solving
-1f + fx = 4 + 2x + 2x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-4 + -1f + fx + -2x + -2x2 = 4 + 2x + 2x2 + -4 + -2x + -2x2

Reorder the terms:
-4 + -1f + fx + -2x + -2x2 = 4 + -4 + 2x + -2x + 2x2 + -2x2

Combine like terms: 4 + -4 = 0
-4 + -1f + fx + -2x + -2x2 = 0 + 2x + -2x + 2x2 + -2x2
-4 + -1f + fx + -2x + -2x2 = 2x + -2x + 2x2 + -2x2

Combine like terms: 2x + -2x = 0
-4 + -1f + fx + -2x + -2x2 = 0 + 2x2 + -2x2
-4 + -1f + fx + -2x + -2x2 = 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
-4 + -1f + fx + -2x + -2x2 = 0

The solution to this equation could not be determined.

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